13401000414113 has 4 divisors (see below), whose sum is σ = 14431846599828. Its totient is φ = 12370154228400.

The previous prime is 13401000414107. The next prime is 13401000414157. The reversal of 13401000414113 is 31141400010431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 4328326294369 + 9072674119744 = 2080463^2 + 3012088^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13401000414113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13401000410113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 515423092838 + ... + 515423092863.

It is an arithmetic number, because the mean of its divisors is an integer number (3607961649957).

Almost surely, 2^{13401000414113} is an apocalyptic number.

13401000414113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13401000414113 is a deficient number, since it is larger than the sum of its proper divisors (1030846185715).

13401000414113 is a wasteful number, since it uses less digits than its factorization.

13401000414113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1030846185714.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 13401000414113 its reverse (31141400010431), we get a palindrome (44542400424544).

The spelling of 13401000414113 in words is "thirteen trillion, four hundred one billion, four hundred fourteen thousand, one hundred thirteen".