Base | Representation |
---|---|
bin | 10011100000000100010… |
… | …101000101010011001111 |
3 | 11202010001001011001221121 |
4 | 103200010111011103033 |
5 | 133424012210310301 |
6 | 2503345021541411 |
7 | 165550662503533 |
oct | 23400425052317 |
9 | 4663031131847 |
10 | 1340102431951 |
11 | 477374982938 |
12 | 197879714867 |
13 | 994a946240a |
14 | 48c0b5bbbc3 |
15 | 24cd48e23a1 |
hex | 138045454cf |
1340102431951 has 2 divisors, whose sum is σ = 1340102431952. Its totient is φ = 1340102431950.
The previous prime is 1340102431937. The next prime is 1340102431961. The reversal of 1340102431951 is 1591342010431.
It is a strong prime.
It is an emirp because it is prime and its reverse (1591342010431) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1340102431951 - 217 = 1340102300879 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1340102431901) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670051215975 + 670051215976.
It is an arithmetic number, because the mean of its divisors is an integer number (670051215976).
Almost surely, 21340102431951 is an apocalyptic number.
1340102431951 is a deficient number, since it is larger than the sum of its proper divisors (1).
1340102431951 is an equidigital number, since it uses as much as digits as its factorization.
1340102431951 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12960, while the sum is 34.
The spelling of 1340102431951 in words is "one trillion, three hundred forty billion, one hundred two million, four hundred thirty-one thousand, nine hundred fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.066 sec. • engine limits •