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1340103133 is a prime number
BaseRepresentation
bin100111111100000…
…0101100111011101
310110101122021220101
41033320011213131
510221031300013
6340551021101
745131455135
oct11770054735
93411567811
101340103133
116284a9356
1231496a791
13184839745
14c9d9dac5
157c9b28dd
hex4fe059dd

1340103133 has 2 divisors, whose sum is σ = 1340103134. Its totient is φ = 1340103132.

The previous prime is 1340103097. The next prime is 1340103157. The reversal of 1340103133 is 3313010431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 794506969 + 545596164 = 28187^2 + 23358^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340103133 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1340103133.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340103733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670051566 + 670051567.

It is an arithmetic number, because the mean of its divisors is an integer number (670051567).

Almost surely, 21340103133 is an apocalyptic number.

It is an amenable number.

1340103133 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340103133 is an equidigital number, since it uses as much as digits as its factorization.

1340103133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 19.

The square root of 1340103133 is about 36607.4190977731. The cubic root of 1340103133 is about 1102.5020546613.

Adding to 1340103133 its reverse (3313010431), we get a palindrome (4653113564).

The spelling of 1340103133 in words is "one billion, three hundred forty million, one hundred three thousand, one hundred thirty-three".