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1340103201141 = 3446701067047
BaseRepresentation
bin10011100000000100011…
…000000001000101110101
311202010001002121011002010
4103200010120001011311
5133424012404414031
62503345050234433
7165551002156215
oct23400430010565
94663032534063
101340103201141
11477375358831
12197879a25a19
13994a9671563
1448c0b73c245
1524cd49e5246
hex13804601175

1340103201141 has 4 divisors (see below), whose sum is σ = 1786804268192. Its totient is φ = 893402134092.

The previous prime is 1340103201121. The next prime is 1340103201193. The reversal of 1340103201141 is 1411023010431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1340103201141 - 26 = 1340103201077 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340103201121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 223350533521 + ... + 223350533526.

It is an arithmetic number, because the mean of its divisors is an integer number (446701067048).

Almost surely, 21340103201141 is an apocalyptic number.

It is an amenable number.

1340103201141 is a deficient number, since it is larger than the sum of its proper divisors (446701067051).

1340103201141 is an equidigital number, since it uses as much as digits as its factorization.

1340103201141 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 446701067050.

The product of its (nonzero) digits is 288, while the sum is 21.

Adding to 1340103201141 its reverse (1411023010431), we get a palindrome (2751126211572).

The spelling of 1340103201141 in words is "one trillion, three hundred forty billion, one hundred three million, two hundred one thousand, one hundred forty-one".

Divisors: 1 3 446701067047 1340103201141