13401040421 has 2 divisors, whose sum is σ = 13401040422. Its totient is φ = 13401040420.

The previous prime is 13401040409. The next prime is 13401040427. The reversal of 13401040421 is 12404010431.

13401040421 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 7671307396 + 5729733025 = 87586^2 + 75695^2 .

It is a cyclic number.

It is not a de Polignac number, because 13401040421 - 2¹⁸ = 13400778277 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13401040393 and 13401040402.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401040427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700520210 + 6700520211.

It is an arithmetic number, because the mean of its divisors is an integer number (6700520211).

Almost surely, 2^13401040421 is an apocalyptic number.

It is an amenable number.

13401040421 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401040421 is an equidigital number, since it uses as much as digits as its factorization.

13401040421 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 13401040421 its reverse (12404010431), we get a palindrome (25805050852).

The spelling of 13401040421 in words is "thirteen billion, four hundred one million, forty thousand, four hundred twenty-one".