134010419 has 2 divisors, whose sum is σ = 134010420. Its totient is φ = 134010418.

The previous prime is 134010413. The next prime is 134010433. The reversal of 134010419 is 914010431.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-134010419 is a prime.

It is a super-2 number, since 2×134010419² = 35917584801111122, which contains 22 as substring.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 134010394 and 134010403.

It is not a weakly prime, because it can be changed into another prime (134010413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67005209 + 67005210.

It is an arithmetic number, because the mean of its divisors is an integer number (67005210).

Almost surely, 2^134010419 is an apocalyptic number.

134010419 is a deficient number, since it is larger than the sum of its proper divisors (1).

134010419 is an equidigital number, since it uses as much as digits as its factorization.

134010419 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 23.

The square root of 134010419 is about 11576.2869262990. The cubic root of 134010419 is about 511.7362571382.

The spelling of 134010419 in words is "one hundred thirty-four million, ten thousand, four hundred nineteen".