134010413 has 2 divisors, whose sum is σ = 134010414. Its totient is φ = 134010412.

The previous prime is 134010367. The next prime is 134010419. The reversal of 134010413 is 314010431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73994404 + 60016009 = 8602^2 + 7747^2 .

It is a cyclic number.

It is not a de Polignac number, because 134010413 - 2¹⁰ = 134009389 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 134010391 and 134010400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134010419) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67005206 + 67005207.

It is an arithmetic number, because the mean of its divisors is an integer number (67005207).

Almost surely, 2^134010413 is an apocalyptic number.

It is an amenable number.

134010413 is a deficient number, since it is larger than the sum of its proper divisors (1).

134010413 is an equidigital number, since it uses as much as digits as its factorization.

134010413 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 134010413 is about 11576.2866671485. The cubic root of 134010413 is about 511.7362495010.

Adding to 134010413 its reverse (314010431), we get a palindrome (448020844).

The spelling of 134010413 in words is "one hundred thirty-four million, ten thousand, four hundred thirteen".