1340111 has 4 divisors (see below), whose sum is σ = 1368672. Its totient is φ = 1311552.

The previous prime is 1340107. The next prime is 1340113. The reversal of 1340111 is 1110431.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1110431 = 7 ⋅158633.

It is a cyclic number.

It is not a de Polignac number, because 1340111 - 2² = 1340107 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340092 and 1340101.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14210 + ... + 14303.

It is an arithmetic number, because the mean of its divisors is an integer number (342168).

2^1340111 is an apocalyptic number.

1340111 is a deficient number, since it is larger than the sum of its proper divisors (28561).

1340111 is an equidigital number, since it uses as much as digits as its factorization.

1340111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 28560.

The product of its (nonzero) digits is 12, while the sum is 11.

The square root of 1340111 is about 1157.6316339838. The cubic root of 1340111 is about 110.2504212049.

Adding to 1340111 its reverse (1110431), we get a palindrome (2450542).

The spelling of 1340111 in words is "one million, three hundred forty thousand, one hundred eleven".