1340112113 has 8 divisors (see below), whose sum is σ = 1384024320. Its totient is φ = 1296242640.

The previous prime is 1340112083. The next prime is 1340112131. The reversal of 1340112113 is 3112110431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1340112113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340112091 and 1340112100.

It is not an unprimeable number, because it can be changed into a prime (1340112413) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 60743 + ... + 79811.

It is an arithmetic number, because the mean of its divisors is an integer number (173003040).

Almost surely, 2^1340112113 is an apocalyptic number.

It is an amenable number.

1340112113 is a deficient number, since it is larger than the sum of its proper divisors (43912207).

1340112113 is a wasteful number, since it uses less digits than its factorization.

1340112113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 21367.

The product of its (nonzero) digits is 72, while the sum is 17.

The square root of 1340112113 is about 36607.5417503006. The cubic root of 1340112113 is about 1102.5045172694.

Adding to 1340112113 its reverse (3112110431), we get a palindrome (4452222544).

The spelling of 1340112113 in words is "one billion, three hundred forty million, one hundred twelve thousand, one hundred thirteen".