134011303 has 2 divisors, whose sum is σ = 134011304. Its totient is φ = 134011302.

The previous prime is 134011301. The next prime is 134011331. The reversal of 134011303 is 303110431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 134011303 - 2¹ = 134011301 is a prime.

Together with 134011301, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134011301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67005651 + 67005652.

It is an arithmetic number, because the mean of its divisors is an integer number (67005652).

Almost surely, 2^134011303 is an apocalyptic number.

134011303 is a deficient number, since it is larger than the sum of its proper divisors (1).

134011303 is an equidigital number, since it uses as much as digits as its factorization.

134011303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 16.

The square root of 134011303 is about 11576.3251077360. The cubic root of 134011303 is about 511.7373823588.

Adding to 134011303 its reverse (303110431), we get a palindrome (437121734).

The spelling of 134011303 in words is "one hundred thirty-four million, eleven thousand, three hundred three".