134011313 has 8 divisors (see below), whose sum is σ = 141175200. Its totient is φ = 126858528.

The previous prime is 134011303. The next prime is 134011331. The reversal of 134011313 is 313110431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 134011313 - 2⁸ = 134011057 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 134011291 and 134011300.

It is not an unprimeable number, because it can be changed into a prime (134011303) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 36098 + ... + 39636.

It is an arithmetic number, because the mean of its divisors is an integer number (17646900).

Almost surely, 2^134011313 is an apocalyptic number.

It is an amenable number.

134011313 is a deficient number, since it is larger than the sum of its proper divisors (7163887).

134011313 is a wasteful number, since it uses less digits than its factorization.

134011313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5551.

The product of its (nonzero) digits is 108, while the sum is 17.

The square root of 134011313 is about 11576.3255396520. The cubic root of 134011313 is about 511.7373950875.

Adding to 134011313 its reverse (313110431), we get a palindrome (447121744).

The spelling of 134011313 in words is "one hundred thirty-four million, eleven thousand, three hundred thirteen".