1340113551321 has 8 divisors (see below), whose sum is σ = 1811984520384. Its totient is φ = 880825808240.

The previous prime is 1340113551299. The next prime is 1340113551341. The reversal of 1340113551321 is 1231553110431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1340113551321 - 2³¹ = 1337966067673 is a prime.

It is not an unprimeable number, because it can be changed into a prime (1340113551341) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3145806246 + ... + 3145806671.

It is an arithmetic number, because the mean of its divisors is an integer number (226498065048).

Almost surely, 2^{1340113551321} is an apocalyptic number.

It is an amenable number.

1340113551321 is a deficient number, since it is larger than the sum of its proper divisors (471870969063).

1340113551321 is an equidigital number, since it uses as much as digits as its factorization.

1340113551321 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6291612991.

The product of its (nonzero) digits is 5400, while the sum is 30.

Adding to 1340113551321 its reverse (1231553110431), we get a palindrome (2571666661752).

The spelling of 1340113551321 in words is "one trillion, three hundred forty billion, one hundred thirteen million, five hundred fifty-one thousand, three hundred twenty-one".