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1340113551342 = 23223352258557
BaseRepresentation
bin10011100000000100111…
…111011111111111101110
311202010001211001222212220
4103200010333133333232
5133424023032120332
62503350100140210
7165551156144556
oct23400477377756
94663054058786
101340113551342
11477380188015
12197881397666
13994ab856637
1448c0cc74166
1524cd588bd2c
hex13804fdffee

1340113551342 has 8 divisors (see below), whose sum is σ = 2680227102696. Its totient is φ = 446704517112.

The previous prime is 1340113551341. The next prime is 1340113551353. The reversal of 1340113551342 is 2431553110431.

It is a sphenic number, since it is the product of 3 distinct primes.

1340113551342 is an admirable number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340113551341) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 111676129273 + ... + 111676129284.

It is an arithmetic number, because the mean of its divisors is an integer number (335028387837).

Almost surely, 21340113551342 is an apocalyptic number.

1340113551342 is a primitive abundant number, since it is smaller than the sum of its proper divisors, none of which is abundant.

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1340113551342 is a wasteful number, since it uses less digits than its factorization.

1340113551342 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 223352258562.

The product of its (nonzero) digits is 21600, while the sum is 33.

Adding to 1340113551342 its reverse (2431553110431), we get a palindrome (3771666661773).

The spelling of 1340113551342 in words is "one trillion, three hundred forty billion, one hundred thirteen million, five hundred fifty-one thousand, three hundred forty-two".

Divisors: 1 2 3 6 223352258557 446704517114 670056775671 1340113551342