13401140111 has 2 divisors, whose sum is σ = 13401140112. Its totient is φ = 13401140110.

The previous prime is 13401140099. The next prime is 13401140119. The reversal of 13401140111 is 11104110431.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13401140111 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13401140111.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401140119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700570055 + 6700570056.

It is an arithmetic number, because the mean of its divisors is an integer number (6700570056).

Almost surely, 2^13401140111 is an apocalyptic number.

13401140111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401140111 is an equidigital number, since it uses as much as digits as its factorization.

13401140111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 13401140111 its reverse (11104110431), we get a palindrome (24505250542).

The spelling of 13401140111 in words is "thirteen billion, four hundred one million, one hundred forty thousand, one hundred eleven".