Search a number
-
+
13401141343 is a prime number
BaseRepresentation
bin11000111101100010…
…10011000001011111
31021120221121111221021
430132301103001133
5204421143010333
610053440545011
7653043551632
oct143661230137
937527544837
1013401141343
11575765a927
122720022167
131357522945
14911b49c19
1553678d82d
hex31ec5305f

13401141343 has 2 divisors, whose sum is σ = 13401141344. Its totient is φ = 13401141342.

The previous prime is 13401141283. The next prime is 13401141433. The reversal of 13401141343 is 34314110431.

It is a happy number.

Together with next prime (13401141433) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (34314110431) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13401141343 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401141643) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700570671 + 6700570672.

It is an arithmetic number, because the mean of its divisors is an integer number (6700570672).

Almost surely, 213401141343 is an apocalyptic number.

13401141343 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401141343 is an equidigital number, since it uses as much as digits as its factorization.

13401141343 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13401141343 its reverse (34314110431), we get a palindrome (47715251774).

The spelling of 13401141343 in words is "thirteen billion, four hundred one million, one hundred forty-one thousand, three hundred forty-three".