Base | Representation |
---|---|
bin | 1100001100000011001001… |
… | …0011111001101011100011 |
3 | 1202110010200122000121102210 |
4 | 3003000302103321223203 |
5 | 3224031014330310230 |
6 | 44300222154413203 |
7 | 2552125535605050 |
oct | 303006223715343 |
9 | 52403618017383 |
10 | 13401142041315 |
11 | 42a7435351696 |
12 | 1605293431203 |
13 | 762950aa7142 |
14 | 344893b4c027 |
15 | 1838db46ceb0 |
hex | c30324f9ae3 |
13401142041315 has 16 divisors (see below), whose sum is σ = 24504945447168. Its totient is φ = 6126236361696.
The previous prime is 13401142041307. The next prime is 13401142041317. The reversal of 13401142041315 is 51314024110431.
It is a happy number.
It is not a de Polignac number, because 13401142041315 - 23 = 13401142041307 is a prime.
It is not an unprimeable number, because it can be changed into a prime (13401142041317) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 63814961997 + ... + 63814962206.
It is an arithmetic number, because the mean of its divisors is an integer number (1531559090448).
Almost surely, 213401142041315 is an apocalyptic number.
13401142041315 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13401142041315 is a deficient number, since it is larger than the sum of its proper divisors (11103803405853).
13401142041315 is a wasteful number, since it uses less digits than its factorization.
13401142041315 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 127629924218.
The product of its (nonzero) digits is 5760, while the sum is 30.
Adding to 13401142041315 its reverse (51314024110431), we get a palindrome (64715166151746).
The spelling of 13401142041315 in words is "thirteen trillion, four hundred one billion, one hundred forty-two million, forty-one thousand, three hundred fifteen".
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