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134012113330423 is a prime number
BaseRepresentation
bin11110011110001000100000…
…011010010010000011110111
3122120111102200121001221011111
4132132020200122102003313
5120031123302003033143
61153004152010415451
740141025045263666
oct3636104032220367
9576442617057144
10134012113330423
1139778244317279
1213044541731587
1359a1398b45653
1425143141baddd
151075e68c0d99d
hex79e2206920f7

134012113330423 has 2 divisors, whose sum is σ = 134012113330424. Its totient is φ = 134012113330422.

The previous prime is 134012113330367. The next prime is 134012113330477. The reversal of 134012113330423 is 324033311210431.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 134012113330423 - 233 = 134003523395831 is a prime.

It is a super-2 number, since 2×1340121133304232 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134012113331423) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67006056665211 + 67006056665212.

It is an arithmetic number, because the mean of its divisors is an integer number (67006056665212).

Almost surely, 2134012113330423 is an apocalyptic number.

134012113330423 is a deficient number, since it is larger than the sum of its proper divisors (1).

134012113330423 is an equidigital number, since it uses as much as digits as its factorization.

134012113330423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 134012113330423 its reverse (324033311210431), we get a palindrome (458045424540854).

The spelling of 134012113330423 in words is "one hundred thirty-four trillion, twelve billion, one hundred thirteen million, three hundred thirty thousand, four hundred twenty-three".