134012113330477 has 2 divisors, whose sum is σ = 134012113330478. Its totient is φ = 134012113330476.

The previous prime is 134012113330423. The next prime is 134012113330517. The reversal of 134012113330477 is 774033311210431.

It is an a-pointer prime, because the next prime (134012113330517) can be obtained adding 134012113330477 to its sum of digits (40).

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 80700415522281 + 53311697808196 = 8983341^2 + 7301486^2 .

It is a cyclic number.

It is not a de Polignac number, because 134012113330477 - 2¹⁵ = 134012113297709 is a prime.

It is a super-2 number, since 2×134012113330477² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134012113331477) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67006056665238 + 67006056665239.

It is an arithmetic number, because the mean of its divisors is an integer number (67006056665239).

Almost surely, 2^{134012113330477} is an apocalyptic number.

It is an amenable number.

134012113330477 is a deficient number, since it is larger than the sum of its proper divisors (1).

134012113330477 is an equidigital number, since it uses as much as digits as its factorization.

134012113330477 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 127008, while the sum is 40.

The spelling of 134012113330477 in words is "one hundred thirty-four trillion, twelve billion, one hundred thirteen million, three hundred thirty thousand, four hundred seventy-seven".