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13401211342 = 26700605671
BaseRepresentation
bin11000111101100011…
…00100000111001110
31021120221202001221211
430132301210013032
5204421202230332
610053442245034
7653044263001
oct143661440716
937527661854
1013401211342
1157576a8482
12272005677a
13135754876c
14911b67538
155367a4447
hex31ec641ce

13401211342 has 4 divisors (see below), whose sum is σ = 20101817016. Its totient is φ = 6700605670.

The previous prime is 13401211339. The next prime is 13401211387. The reversal of 13401211342 is 24311210431.

13401211342 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3350302834 + ... + 3350302837.

It is an arithmetic number, because the mean of its divisors is an integer number (5025454254).

Almost surely, 213401211342 is an apocalyptic number.

13401211342 is a deficient number, since it is larger than the sum of its proper divisors (6700605674).

13401211342 is an equidigital number, since it uses as much as digits as its factorization.

13401211342 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6700605673.

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 13401211342 its reverse (24311210431), we get a palindrome (37712421773).

The spelling of 13401211342 in words is "thirteen billion, four hundred one million, two hundred eleven thousand, three hundred forty-two".

Divisors: 1 2 6700605671 13401211342