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1340121313469 is a prime number
BaseRepresentation
bin10011100000000101011…
…101000111000010111101
311202010002100200100112002
4103200011131013002331
5133424032024012334
62503350534352045
7165551312133641
oct23400535070275
94663070610462
101340121313469
114773845a98a4
12197883abb625
13994b0343703
1448c0dcd4c21
1524cd63c1b7e
hex138057470bd

1340121313469 has 2 divisors, whose sum is σ = 1340121313470. Its totient is φ = 1340121313468.

The previous prime is 1340121313423. The next prime is 1340121313477. The reversal of 1340121313469 is 9643131210431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 762845028100 + 577276285369 = 873410^2 + 759787^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340121313469 is a prime.

It is a super-2 number, since 2×13401213134692 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340121313169) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670060656734 + 670060656735.

It is an arithmetic number, because the mean of its divisors is an integer number (670060656735).

Almost surely, 21340121313469 is an apocalyptic number.

It is an amenable number.

1340121313469 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340121313469 is an equidigital number, since it uses as much as digits as its factorization.

1340121313469 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 46656, while the sum is 38.

The spelling of 1340121313469 in words is "one trillion, three hundred forty billion, one hundred twenty-one million, three hundred thirteen thousand, four hundred sixty-nine".