1340121313423 has 2 divisors, whose sum is σ = 1340121313424. Its totient is φ = 1340121313422.

The previous prime is 1340121313411. The next prime is 1340121313469. The reversal of 1340121313423 is 3243131210431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1340121313423 - 2²⁵ = 1340087758991 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340121313391 and 1340121313400.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340121313523) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670060656711 + 670060656712.

It is an arithmetic number, because the mean of its divisors is an integer number (670060656712).

Almost surely, 2^{1340121313423} is an apocalyptic number.

1340121313423 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340121313423 is an equidigital number, since it uses as much as digits as its factorization.

1340121313423 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 1340121313423 its reverse (3243131210431), we get a palindrome (4583252523854).

The spelling of 1340121313423 in words is "one trillion, three hundred forty billion, one hundred twenty-one million, three hundred thirteen thousand, four hundred twenty-three".