13401216733 has 2 divisors, whose sum is σ = 13401216734. Its totient is φ = 13401216732.

The previous prime is 13401216727. The next prime is 13401216749. The reversal of 13401216733 is 33761210431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9184922244 + 4216294489 = 95838^2 + 64933^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13401216733 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13401216695 and 13401216704.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401216793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700608366 + 6700608367.

It is an arithmetic number, because the mean of its divisors is an integer number (6700608367).

Almost surely, 2^13401216733 is an apocalyptic number.

It is an amenable number.

13401216733 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401216733 is an equidigital number, since it uses as much as digits as its factorization.

13401216733 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 9072, while the sum is 31.

The spelling of 13401216733 in words is "thirteen billion, four hundred one million, two hundred sixteen thousand, seven hundred thirty-three".