Base | Representation |
---|---|
bin | 11000111101100011… |
… | …00101011011010111 |
3 | 1021120221202100100021 |
4 | 30132301211123113 |
5 | 204421202413402 |
6 | 10053442330011 |
7 | 653044314463 |
oct | 143661453327 |
9 | 37527670307 |
10 | 13401216727 |
11 | 5757701528 |
12 | 2720059907 |
13 | 135754b052 |
14 | 911b694a3 |
15 | 5367a5d37 |
hex | 31ec656d7 |
13401216727 has 2 divisors, whose sum is σ = 13401216728. Its totient is φ = 13401216726.
The previous prime is 13401216721. The next prime is 13401216733. The reversal of 13401216727 is 72761210431.
It is a balanced prime because it is at equal distance from previous prime (13401216721) and next prime (13401216733).
It is a cyclic number.
It is not a de Polignac number, because 13401216727 - 219 = 13400692439 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13401216692 and 13401216701.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13401216721) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700608363 + 6700608364.
It is an arithmetic number, because the mean of its divisors is an integer number (6700608364).
Almost surely, 213401216727 is an apocalyptic number.
13401216727 is a deficient number, since it is larger than the sum of its proper divisors (1).
13401216727 is an equidigital number, since it uses as much as digits as its factorization.
13401216727 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14112, while the sum is 34.
The spelling of 13401216727 in words is "thirteen billion, four hundred one million, two hundred sixteen thousand, seven hundred twenty-seven".
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