1340122111 has 2 divisors, whose sum is σ = 1340122112. Its totient is φ = 1340122110.

The previous prime is 1340122097. The next prime is 1340122127. The reversal of 1340122111 is 1112210431.

It is an a-pointer prime, because the next prime (1340122127) can be obtained adding 1340122111 to its sum of digits (16).

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1340122111 - 2¹¹ = 1340120063 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340122171) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670061055 + 670061056.

It is an arithmetic number, because the mean of its divisors is an integer number (670061056).

Almost surely, 2^1340122111 is an apocalyptic number.

1340122111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340122111 is an equidigital number, since it uses as much as digits as its factorization.

1340122111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 16.

The square root of 1340122111 is about 36607.6783066067. The cubic root of 1340122111 is about 1102.5072590332.

Adding to 1340122111 its reverse (1112210431), we get a palindrome (2452332542).

The spelling of 1340122111 in words is "one billion, three hundred forty million, one hundred twenty-two thousand, one hundred eleven".