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134012243044223 = 263509552254921
BaseRepresentation
bin11110011110001000101000…
…001001000110011101111111
3122120111110000122011002001022
4132132020220021012131333
5120031124033204403343
61153004212522534355
740141031211653225
oct3636105011063577
9576443018132038
10134012243044223
1139778300563165
12130445790673bb
1359a13b9990a8b
142514327504b15
151075e752d2568
hex79e22824677f

134012243044223 has 4 divisors (see below), whose sum is σ = 134521795299408. Its totient is φ = 133502690789040.

The previous prime is 134012243044213. The next prime is 134012243044237. The reversal of 134012243044223 is 322440342210431.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134012243044223 - 216 = 134012242978687 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134012243044213) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 254776127198 + ... + 254776127723.

It is an arithmetic number, because the mean of its divisors is an integer number (33630448824852).

Almost surely, 2134012243044223 is an apocalyptic number.

134012243044223 is a deficient number, since it is larger than the sum of its proper divisors (509552255185).

134012243044223 is an equidigital number, since it uses as much as digits as its factorization.

134012243044223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 509552255184.

The product of its (nonzero) digits is 110592, while the sum is 35.

Adding to 134012243044223 its reverse (322440342210431), we get a palindrome (456452585254654).

The spelling of 134012243044223 in words is "one hundred thirty-four trillion, twelve billion, two hundred forty-three million, forty-four thousand, two hundred twenty-three".

Divisors: 1 263 509552254921 134012243044223