1340124214333 has 2 divisors, whose sum is σ = 1340124214334. Its totient is φ = 1340124214332.

The previous prime is 1340124214321. The next prime is 1340124214343. The reversal of 1340124214333 is 3334124210431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1210435639204 + 129688575129 = 1100198^2 + 360123^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340124214333 - 2²⁹ = 1339587343421 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1340124214295 and 1340124214304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340124214343) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670062107166 + 670062107167.

It is an arithmetic number, because the mean of its divisors is an integer number (670062107167).

Almost surely, 2^{1340124214333} is an apocalyptic number.

It is an amenable number.

1340124214333 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340124214333 is an equidigital number, since it uses as much as digits as its factorization.

1340124214333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1340124214333 its reverse (3334124210431), we get a palindrome (4674248424764).

The spelling of 1340124214333 in words is "one trillion, three hundred forty billion, one hundred twenty-four million, two hundred fourteen thousand, three hundred thirty-three".