Base | Representation |
---|---|
bin | 111110011001111000… |
… | …0110100100100000001 |
3 | 110210220120000102101220 |
4 | 1330303300310210001 |
5 | 4143424140004101 |
6 | 141321531145253 |
7 | 12452644536564 |
oct | 1746360644401 |
9 | 423816012356 |
10 | 134012422401 |
11 | 5191a578500 |
12 | 21b805a5229 |
13 | c839255580 |
14 | 66b43344db |
15 | 374523e636 |
hex | 1f33c34901 |
134012422401 has 48 divisors (see below), whose sum is σ = 212120529600. Its totient is φ = 74756246400.
The previous prime is 134012422331. The next prime is 134012422447. The reversal of 134012422401 is 104224210431.
It is a de Polignac number, because none of the positive numbers 2k-134012422401 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (134012424401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1606246 + ... + 1687616.
It is an arithmetic number, because the mean of its divisors is an integer number (4419177700).
Almost surely, 2134012422401 is an apocalyptic number.
134012422401 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
134012422401 is a deficient number, since it is larger than the sum of its proper divisors (78108107199).
134012422401 is a wasteful number, since it uses less digits than its factorization.
134012422401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81758 (or 81747 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 24.
Adding to 134012422401 its reverse (104224210431), we get a palindrome (238236632832).
The spelling of 134012422401 in words is "one hundred thirty-four billion, twelve million, four hundred twenty-two thousand, four hundred one".
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