13401243314 has 4 divisors (see below), whose sum is σ = 20101864974. Its totient is φ = 6700621656.

The previous prime is 13401243311. The next prime is 13401243347. The reversal of 13401243314 is 41334210431.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 41334210431 = 17 ⋅2431424143.

It can be written as a sum of positive squares in only one way, i.e., 12589962025 + 811281289 = 112205^2 + 28483^2 .

It is a super-2 number, since 2×13401243314² (a number of 21 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (13401243311) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3350310827 + ... + 3350310830.

Almost surely, 2^13401243314 is an apocalyptic number.

13401243314 is a deficient number, since it is larger than the sum of its proper divisors (6700621660).

13401243314 is an equidigital number, since it uses as much as digits as its factorization.

13401243314 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6700621659.

The product of its (nonzero) digits is 3456, while the sum is 26.

Adding to 13401243314 its reverse (41334210431), we get a palindrome (54735453745).

The spelling of 13401243314 in words is "thirteen billion, four hundred one million, two hundred forty-three thousand, three hundred fourteen".