13401250629071 has 2 divisors, whose sum is σ = 13401250629072. Its totient is φ = 13401250629070.

The previous prime is 13401250629047. The next prime is 13401250629133. The reversal of 13401250629071 is 17092605210431.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13401250629071 is a prime.

It is a super-3 number, since 3×13401250629071³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401250629001) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700625314535 + 6700625314536.

It is an arithmetic number, because the mean of its divisors is an integer number (6700625314536).

Almost surely, 2^{13401250629071} is an apocalyptic number.

13401250629071 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401250629071 is an equidigital number, since it uses as much as digits as its factorization.

13401250629071 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90720, while the sum is 41.

The spelling of 13401250629071 in words is "thirteen trillion, four hundred one billion, two hundred fifty million, six hundred twenty-nine thousand, seventy-one".