13401250629133 has 2 divisors, whose sum is σ = 13401250629134. Its totient is φ = 13401250629132.

The previous prime is 13401250629071. The next prime is 13401250629191. The reversal of 13401250629133 is 33192605210431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10993223253609 + 2408027375524 = 3315603^2 + 1551782^2 .

It is a cyclic number.

It is not a de Polignac number, because 13401250629133 - 2³⁷ = 13263811675661 is a prime.

It is a super-3 number, since 3×13401250629133³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401250627133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700625314566 + 6700625314567.

It is an arithmetic number, because the mean of its divisors is an integer number (6700625314567).

Almost surely, 2^{13401250629133} is an apocalyptic number.

It is an amenable number.

13401250629133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401250629133 is an equidigital number, since it uses as much as digits as its factorization.

13401250629133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 116640, while the sum is 40.

Adding to 13401250629133 its reverse (33192605210431), we get a palindrome (46593855839564).

The spelling of 13401250629133 in words is "thirteen trillion, four hundred one billion, two hundred fifty million, six hundred twenty-nine thousand, one hundred thirty-three".