13401300121 has 8 divisors (see below), whose sum is σ = 14631568704. Its totient is φ = 12173026320.

The previous prime is 13401300103. The next prime is 13401300151. The reversal of 13401300121 is 12100310431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13401300121 - 2⁵ = 13401300089 is a prime.

It is a super-2 number, since 2×13401300121² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13401300095 and 13401300104.

It is not an unprimeable number, because it can be changed into a prime (13401300151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 484626 + ... + 511531.

It is an arithmetic number, because the mean of its divisors is an integer number (1828946088).

Almost surely, 2^13401300121 is an apocalyptic number.

13401300121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13401300121 is a deficient number, since it is larger than the sum of its proper divisors (1230268583).

13401300121 is a wasteful number, since it uses less digits than its factorization.

13401300121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 997391.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13401300121 its reverse (12100310431), we get a palindrome (25501610552).

The spelling of 13401300121 in words is "thirteen billion, four hundred one million, three hundred thousand, one hundred twenty-one".