134013004103 has 4 divisors (see below), whose sum is σ = 146196004488. Its totient is φ = 121830003720.

The previous prime is 134013004067. The next prime is 134013004109. The reversal of 134013004103 is 301400310431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 134013004103 - 2⁶ = 134013004039 is a prime.

It is a super-4 number, since 4×134013004103⁴ (a number of 46 digits) contains 4444 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (134013004109) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6091500176 + ... + 6091500197.

It is an arithmetic number, because the mean of its divisors is an integer number (36549001122).

Almost surely, 2^134013004103 is an apocalyptic number.

134013004103 is a deficient number, since it is larger than the sum of its proper divisors (12183000385).

134013004103 is a wasteful number, since it uses less digits than its factorization.

134013004103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12183000384.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 134013004103 its reverse (301400310431), we get a palindrome (435413314534).

The spelling of 134013004103 in words is "one hundred thirty-four billion, thirteen million, four thousand, one hundred three".