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134013467527 is a prime number
BaseRepresentation
bin111110011001111010…
…0110011101110000111
3110210220121222112001021
41330303310303232013
54143424421430102
6141322005412011
712452656451602
oct1746364635607
9423817875037
10134013467527
1151920121745
1221b80a0a007
13c8395301a4
1466b4527339
153745399137
hex1f33d33b87

134013467527 has 2 divisors, whose sum is σ = 134013467528. Its totient is φ = 134013467526.

The previous prime is 134013467521. The next prime is 134013467579. The reversal of 134013467527 is 725764310431.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 134013467527 - 215 = 134013434759 is a prime.

It is a super-2 number, since 2×1340134675272 (a number of 23 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (134013467521) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67006733763 + 67006733764.

It is an arithmetic number, because the mean of its divisors is an integer number (67006733764).

Almost surely, 2134013467527 is an apocalyptic number.

134013467527 is a deficient number, since it is larger than the sum of its proper divisors (1).

134013467527 is an equidigital number, since it uses as much as digits as its factorization.

134013467527 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 423360, while the sum is 43.

Adding to 134013467527 its reverse (725764310431), we get a palindrome (859777777958).

The spelling of 134013467527 in words is "one hundred thirty-four billion, thirteen million, four hundred sixty-seven thousand, five hundred twenty-seven".