1340141011021 has 4 divisors (see below), whose sum is σ = 1340638652412. Its totient is φ = 1339643369632.

The previous prime is 1340141011019. The next prime is 1340141011057. The reversal of 1340141011021 is 1201101410431.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 452409592996 + 887731418025 = 672614^2 + 942195^2 .

It is a cyclic number.

It is not a de Polignac number, because 1340141011021 - 2¹ = 1340141011019 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1340141011021.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340141011421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 248816656 + ... + 248822041.

It is an arithmetic number, because the mean of its divisors is an integer number (335159663103).

Almost surely, 2^{1340141011021} is an apocalyptic number.

It is an amenable number.

1340141011021 is a deficient number, since it is larger than the sum of its proper divisors (497641391).

1340141011021 is an equidigital number, since it uses as much as digits as its factorization.

1340141011021 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 497641390.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 1340141011021 its reverse (1201101410431), we get a palindrome (2541242421452).

The spelling of 1340141011021 in words is "one trillion, three hundred forty billion, one hundred forty-one million, eleven thousand, twenty-one".