Base | Representation |
---|---|
bin | 111110011001111100… |
… | …0011000011101001111 |
3 | 110210220200202010020102 |
4 | 1330303320120131033 |
5 | 4143430141420211 |
6 | 141322041441315 |
7 | 12453000433235 |
oct | 1746370303517 |
9 | 423820663212 |
10 | 134014404431 |
11 | 51920701646 |
12 | 21b811a023b |
13 | c83979a77b |
14 | 66b46cc955 |
15 | 37454d1a3b |
hex | 1f33e1874f |
134014404431 has 2 divisors, whose sum is σ = 134014404432. Its totient is φ = 134014404430.
The previous prime is 134014404409. The next prime is 134014404443. The reversal of 134014404431 is 134404410431.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-134014404431 is a prime.
It is a super-2 number, since 2×1340144044312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 134014404394 and 134014404403.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (134014404401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67007202215 + 67007202216.
It is an arithmetic number, because the mean of its divisors is an integer number (67007202216).
Almost surely, 2134014404431 is an apocalyptic number.
134014404431 is a deficient number, since it is larger than the sum of its proper divisors (1).
134014404431 is an equidigital number, since it uses as much as digits as its factorization.
134014404431 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9216, while the sum is 29.
Adding to 134014404431 its reverse (134404410431), we get a palindrome (268418814862).
The spelling of 134014404431 in words is "one hundred thirty-four billion, fourteen million, four hundred four thousand, four hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •