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134014404403 = 1117716654569
BaseRepresentation
bin111110011001111100…
…0011000011100110011
3110210220200202010012101
41330303320120130303
54143430141420103
6141322041441231
712453000433165
oct1746370303463
9423820663171
10134014404403
1151920701620
1221b811a0217
13c83979a759
1466b46cc935
1537454d1a1d
hex1f33e18733

134014404403 has 8 divisors (see below), whose sum is σ = 154797387120. Its totient is φ = 114664730880.

The previous prime is 134014404401. The next prime is 134014404409. The reversal of 134014404403 is 304404410431.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 134014404403 - 21 = 134014404401 is a prime.

It is a Duffinian number.

It is a zygodrome in base 2.

It is not an unprimeable number, because it can be changed into a prime (134014404401) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 358327098 + ... + 358327471.

It is an arithmetic number, because the mean of its divisors is an integer number (19349673390).

Almost surely, 2134014404403 is an apocalyptic number.

134014404403 is a deficient number, since it is larger than the sum of its proper divisors (20782982717).

134014404403 is a wasteful number, since it uses less digits than its factorization.

134014404403 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 716654597.

The product of its (nonzero) digits is 9216, while the sum is 28.

Adding to 134014404403 its reverse (304404410431), we get a palindrome (438418814834).

The spelling of 134014404403 in words is "one hundred thirty-four billion, fourteen million, four hundred four thousand, four hundred three".

Divisors: 1 11 17 187 716654569 7883200259 12183127673 134014404403