13402002211 has 4 divisors (see below), whose sum is σ = 14432925472. Its totient is φ = 12371078952.

The previous prime is 13402002193. The next prime is 13402002217. The reversal of 13402002211 is 11220020431.

13402002211 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 11220020431 = 881 ⋅12735551.

It is a cyclic number.

It is not a de Polignac number, because 13402002211 - 2⁵ = 13402002179 is a prime.

It is a super-2 number, since 2×13402002211² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13402002217) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 515461611 + ... + 515461636.

It is an arithmetic number, because the mean of its divisors is an integer number (3608231368).

Almost surely, 2^13402002211 is an apocalyptic number.

13402002211 is a deficient number, since it is larger than the sum of its proper divisors (1030923261).

13402002211 is a wasteful number, since it uses less digits than its factorization.

13402002211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1030923260.

The product of its (nonzero) digits is 96, while the sum is 16.

Adding to 13402002211 its reverse (11220020431), we get a palindrome (24622022642).

The spelling of 13402002211 in words is "thirteen billion, four hundred two million, two thousand, two hundred eleven".