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1340201437 is a prime number
BaseRepresentation
bin100111111100001…
…1101100111011101
310110101211021202021
41033320131213131
510221042421222
6340553100141
745132344551
oct11770354735
93411737667
101340201437
116285661a3
123149b7651
13184872403
14c9dc7861
157c9d1ac7
hex4fe1d9dd

1340201437 has 2 divisors, whose sum is σ = 1340201438. Its totient is φ = 1340201436.

The previous prime is 1340201413. The next prime is 1340201459. The reversal of 1340201437 is 7341020431.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1331593081 + 8608356 = 36491^2 + 2934^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1340201437 is a prime.

It is a super-2 number, since 2×13402014372 = 3592279783473729938, which contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1340201497) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 670100718 + 670100719.

It is an arithmetic number, because the mean of its divisors is an integer number (670100719).

Almost surely, 21340201437 is an apocalyptic number.

It is an amenable number.

1340201437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1340201437 is an equidigital number, since it uses as much as digits as its factorization.

1340201437 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 25.

The square root of 1340201437 is about 36608.7617517993. The cubic root of 1340201437 is about 1102.5290122164.

Adding to 1340201437 its reverse (7341020431), we get a palindrome (8681221868).

The spelling of 1340201437 in words is "one billion, three hundred forty million, two hundred one thousand, four hundred thirty-seven".