13402021413 has 8 divisors (see below), whose sum is σ = 19493849376. Its totient is φ = 8122437200.

The previous prime is 13402021397. The next prime is 13402021421. The reversal of 13402021413 is 31412020431.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13402021413 - 2⁴ = 13402021397 is a prime.

It is a super-2 number, since 2×13402021413² (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13402021413.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402021483) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 203060898 + ... + 203060963.

It is an arithmetic number, because the mean of its divisors is an integer number (2436731172).

Almost surely, 2^13402021413 is an apocalyptic number.

It is an amenable number.

13402021413 is a deficient number, since it is larger than the sum of its proper divisors (6091827963).

13402021413 is a wasteful number, since it uses less digits than its factorization.

13402021413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 406121875.

The product of its (nonzero) digits is 576, while the sum is 21.

Adding to 13402021413 its reverse (31412020431), we get a palindrome (44814041844).

The spelling of 13402021413 in words is "thirteen billion, four hundred two million, twenty-one thousand, four hundred thirteen".