1340204003 has 4 divisors (see below), whose sum is σ = 1340278848. Its totient is φ = 1340129160.

The previous prime is 1340203957. The next prime is 1340204009. The reversal of 1340204003 is 3004020431.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3004020431 = 41 ⋅73268791.

It is a cyclic number.

It is not a de Polignac number, because 1340204003 - 2¹² = 1340199907 is a prime.

It is a super-2 number, since 2×1340204003² = 3592293539314448018, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1340204009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 7073 + ... + 52253.

It is an arithmetic number, because the mean of its divisors is an integer number (335069712).

Almost surely, 2^1340204003 is an apocalyptic number.

1340204003 is a deficient number, since it is larger than the sum of its proper divisors (74845).

1340204003 is an equidigital number, since it uses as much as digits as its factorization.

1340204003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 74844.

The product of its (nonzero) digits is 288, while the sum is 17.

The square root of 1340204003 is about 36608.7967980375. The cubic root of 1340204003 is about 1102.5297158638.

Adding to 1340204003 its reverse (3004020431), we get a palindrome (4344224434).

The spelling of 1340204003 in words is "one billion, three hundred forty million, two hundred four thousand, three".