Base | Representation |
---|---|
bin | 10011100000001010011… |
… | …000101010011111110000 |
3 | 11202010022010022222210122 |
4 | 103200022120222133300 |
5 | 133424214213042112 |
6 | 2503403051345412 |
7 | 165553335220523 |
oct | 23401230523760 |
9 | 4663263288718 |
10 | 1340204034032 |
11 | 477417268aa6 |
12 | 1978a7752268 |
13 | 994c45171a6 |
14 | 48c1aca8bba |
15 | 24cdd7b1872 |
hex | 1380a62a7f0 |
1340204034032 has 20 divisors (see below), whose sum is σ = 2686184810520. Its totient is φ = 646995050688.
The previous prime is 1340204033957. The next prime is 1340204034079. The reversal of 1340204034032 is 2304304020431.
It is a super-2 number, since 2×13402040340322 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1340204033992 and 1340204034010.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1444184918 + ... + 1444185845.
It is an arithmetic number, because the mean of its divisors is an integer number (134309240526).
Almost surely, 21340204034032 is an apocalyptic number.
It is an amenable number.
1340204034032 is an abundant number, since it is smaller than the sum of its proper divisors (1345980776488).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1340204034032 is a wasteful number, since it uses less digits than its factorization.
1340204034032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2888370800 (or 2888370794 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 26.
Adding to 1340204034032 its reverse (2304304020431), we get a palindrome (3644508054463).
The spelling of 1340204034032 in words is "one trillion, three hundred forty billion, two hundred four million, thirty-four thousand, thirty-two".
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