Base | Representation |
---|---|
bin | 1111111110100… |
… | …00000001010001 |
3 | 100100011222112012 |
4 | 13333100001101 |
5 | 233302134301 |
6 | 21144312305 |
7 | 3215106236 |
oct | 777200121 |
9 | 310158465 |
10 | 134021201 |
11 | 69719126 |
12 | 38a72695 |
13 | 219c5bb2 |
14 | 13b2978d |
15 | bb74ebb |
hex | 7fd0051 |
134021201 has 2 divisors, whose sum is σ = 134021202. Its totient is φ = 134021200.
The previous prime is 134021189. The next prime is 134021203. The reversal of 134021201 is 102120431.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 68492176 + 65529025 = 8276^2 + 8095^2 .
It is a cyclic number.
It is not a de Polignac number, because 134021201 - 214 = 134004817 is a prime.
It is a Sophie Germain prime.
Together with 134021203, it forms a pair of twin primes.
It is a Chen prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (134021203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67010600 + 67010601.
It is an arithmetic number, because the mean of its divisors is an integer number (67010601).
Almost surely, 2134021201 is an apocalyptic number.
It is an amenable number.
134021201 is a deficient number, since it is larger than the sum of its proper divisors (1).
134021201 is an equidigital number, since it uses as much as digits as its factorization.
134021201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 48, while the sum is 14.
The square root of 134021201 is about 11576.7526102962. The cubic root of 134021201 is about 511.7499809278.
Adding to 134021201 its reverse (102120431), we get a palindrome (236141632).
The spelling of 134021201 in words is "one hundred thirty-four million, twenty-one thousand, two hundred one".
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