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13402120230533 is a prime number
BaseRepresentation
bin1100001100000110110010…
…0111011001011010000101
31202110020012210122202210002
43003001230213121122011
53224040020234334113
644300503220411045
72552162014225466
oct303015447313205
952406183582702
1013402120230533
1142a7897528731
121605506b46a85
13762a78648928
14344947a1cd6d
15183947291c58
hexc306c9d9685

13402120230533 has 2 divisors, whose sum is σ = 13402120230534. Its totient is φ = 13402120230532.

The previous prime is 13402120230517. The next prime is 13402120230589. The reversal of 13402120230533 is 33503202120431.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11627131580164 + 1774988650369 = 3409858^2 + 1332287^2 .

It is a cyclic number.

It is not a de Polignac number, because 13402120230533 - 24 = 13402120230517 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13402120230496 and 13402120230505.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13402120730533) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6701060115266 + 6701060115267.

It is an arithmetic number, because the mean of its divisors is an integer number (6701060115267).

Almost surely, 213402120230533 is an apocalyptic number.

It is an amenable number.

13402120230533 is a deficient number, since it is larger than the sum of its proper divisors (1).

13402120230533 is an equidigital number, since it uses as much as digits as its factorization.

13402120230533 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 29.

Adding to 13402120230533 its reverse (33503202120431), we get a palindrome (46905322350964).

The spelling of 13402120230533 in words is "thirteen trillion, four hundred two billion, one hundred twenty million, two hundred thirty thousand, five hundred thirty-three".