13402143401033 has 4 divisors (see below), whose sum is σ = 13402530210768. Its totient is φ = 13401756591300.

The previous prime is 13402143401021. The next prime is 13402143401039. The reversal of 13402143401033 is 33010434120431.

It is a happy number.

13402143401033 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13402143401033 - 2⁸ = 13402143400777 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13402143400987 and 13402143401005.

It is not an unprimeable number, because it can be changed into a prime (13402143401039) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 193352891 + ... + 193422192.

It is an arithmetic number, because the mean of its divisors is an integer number (3350632552692).

Almost surely, 2^{13402143401033} is an apocalyptic number.

It is an amenable number.

13402143401033 is a deficient number, since it is larger than the sum of its proper divisors (386809735).

13402143401033 is an equidigital number, since it uses as much as digits as its factorization.

13402143401033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 386809734.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 13402143401033 its reverse (33010434120431), we get a palindrome (46412577521464).

The spelling of 13402143401033 in words is "thirteen trillion, four hundred two billion, one hundred forty-three million, four hundred one thousand, thirty-three".