Base | Representation |
---|---|
bin | 10011100000001011000… |
… | …000000001100110101111 |
3 | 11202010022211202012210211 |
4 | 103200023000001212233 |
5 | 133424224333233203 |
6 | 2503404100443251 |
7 | 165553522014121 |
oct | 23401300014657 |
9 | 4663284665724 |
10 | 1340214352303 |
11 | 4774220762a2 |
12 | 1978ab0a9527 |
13 | 994c66ba888 |
14 | 48c1c3d3211 |
15 | 24cde64dc6d |
hex | 1380b0019af |
1340214352303 has 8 divisors (see below), whose sum is σ = 1366007490000. Its totient is φ = 1314439958208.
The previous prime is 1340214352283. The next prime is 1340214352327. The reversal of 1340214352303 is 3032534120431.
It is a happy number.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1340214352303 - 213 = 1340214344111 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1340214352403) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4541478 + ... + 4827571.
It is an arithmetic number, because the mean of its divisors is an integer number (170750936250).
Almost surely, 21340214352303 is an apocalyptic number.
1340214352303 is a deficient number, since it is larger than the sum of its proper divisors (25793137697).
1340214352303 is an equidigital number, since it uses as much as digits as its factorization.
1340214352303 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 9371801.
The product of its (nonzero) digits is 25920, while the sum is 31.
Adding to 1340214352303 its reverse (3032534120431), we get a palindrome (4372748472734).
The spelling of 1340214352303 in words is "one trillion, three hundred forty billion, two hundred fourteen million, three hundred fifty-two thousand, three hundred three".
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