13402211024021 has 4 divisors (see below), whose sum is σ = 13687364450112. Its totient is φ = 13117057597932.

The previous prime is 13402211023997. The next prime is 13402211024099. The reversal of 13402211024021 is 12042011220431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13402211024021 - 2¹⁰ = 13402211022997 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402211024221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 142576712975 + ... + 142576713068.

It is an arithmetic number, because the mean of its divisors is an integer number (3421841112528).

Almost surely, 2^{13402211024021} is an apocalyptic number.

It is an amenable number.

13402211024021 is a deficient number, since it is larger than the sum of its proper divisors (285153426091).

13402211024021 is an equidigital number, since it uses as much as digits as its factorization.

13402211024021 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 285153426090.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 13402211024021 its reverse (12042011220431), we get a palindrome (25444222244452).

The spelling of 13402211024021 in words is "thirteen trillion, four hundred two billion, two hundred eleven million, twenty-four thousand, twenty-one".