1340222333 has 4 divisors (see below), whose sum is σ = 1340301120. Its totient is φ = 1340143548.

The previous prime is 1340222329. The next prime is 1340222357. The reversal of 1340222333 is 3332220431.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 3332220431 = 89 ⋅37440679.

It is a cyclic number.

It is not a de Polignac number, because 1340222333 - 2² = 1340222329 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1340222299 and 1340222308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1340222363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2123 + ... + 51816.

It is an arithmetic number, because the mean of its divisors is an integer number (335075280).

Almost surely, 2^1340222333 is an apocalyptic number.

It is an amenable number.

1340222333 is a deficient number, since it is larger than the sum of its proper divisors (78787).

1340222333 is an equidigital number, since it uses as much as digits as its factorization.

1340222333 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 78786.

The product of its (nonzero) digits is 2592, while the sum is 23.

The square root of 1340222333 is about 36609.0471468461. The cubic root of 1340222333 is about 1102.5347422820.

Adding to 1340222333 its reverse (3332220431), we get a palindrome (4672442764).

The spelling of 1340222333 in words is "one billion, three hundred forty million, two hundred twenty-two thousand, three hundred thirty-three".