13402301420133 has 8 divisors (see below), whose sum is σ = 19855261363200. Its totient is φ = 8934867613404.

The previous prime is 13402301420087. The next prime is 13402301420201. The reversal of 13402301420133 is 33102410320431.

It is a happy number.

13402301420133 is a `hidden beast` number, since 1 + 3 + 4 + 0 + 230 + 1 + 420 + 1 + 3 + 3 = 666.

It is not a de Polignac number, because 13402301420133 - 2⁹ = 13402301419621 is a prime.

It is a Harshad number since it is a multiple of its sum of digits (27), and also a Moran number because the ratio is a prime number: 496381534079 = 13402301420133 / (1 + 3 + 4 + 0 + 2 + 3 + 0 + 1 + 4 + 2 + 0 + 1 + 3 + 3).

It is a junction number, because it is equal to n+sod(n) for n = 13402301420097 and 13402301420106.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402301421133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 248190767013 + ... + 248190767066.

It is an arithmetic number, because the mean of its divisors is an integer number (2481907670400).

Almost surely, 2^{13402301420133} is an apocalyptic number.

It is an amenable number.

13402301420133 is a deficient number, since it is larger than the sum of its proper divisors (6452959943067).

13402301420133 is an equidigital number, since it uses as much as digits as its factorization.

13402301420133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 496381534088 (or 496381534082 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 27.

Adding to 13402301420133 its reverse (33102410320431), we get a palindrome (46504711740564).

The spelling of 13402301420133 in words is "thirteen trillion, four hundred two billion, three hundred one million, four hundred twenty thousand, one hundred thirty-three".