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134023124432 = 248376445277
BaseRepresentation
bin111110011010001100…
…1101001010111010000
3110210221022011010211102
41330310121221113100
54143434404440212
6141322552403532
712453134522051
oct1746431512720
9423838133742
10134023124432
115192561805a
1221b840a65a8
13c83b531832
1466b591c728
1537461555c2
hex1f346695d0

134023124432 has 10 divisors (see below), whose sum is σ = 259669803618. Its totient is φ = 67011562208.

The previous prime is 134023124423. The next prime is 134023124453. The reversal of 134023124432 is 234421320431.

It can be written as a sum of positive squares in only one way, i.e., 104016570256 + 30006554176 = 322516^2 + 173224^2 .

It is a junction number, because it is equal to n+sod(n) for n = 134023124395 and 134023124404.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 4188222623 + ... + 4188222654.

Almost surely, 2134023124432 is an apocalyptic number.

It is an amenable number.

134023124432 is a deficient number, since it is larger than the sum of its proper divisors (125646679186).

134023124432 is an equidigital number, since it uses as much as digits as its factorization.

134023124432 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8376445285 (or 8376445279 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 29.

Adding to 134023124432 its reverse (234421320431), we get a palindrome (368444444863).

The spelling of 134023124432 in words is "one hundred thirty-four billion, twenty-three million, one hundred twenty-four thousand, four hundred thirty-two".

Divisors: 1 2 4 8 16 8376445277 16752890554 33505781108 67011562216 134023124432