13402324343 has 4 divisors (see below), whose sum is σ = 13402558728. Its totient is φ = 13402089960.

The previous prime is 13402324283. The next prime is 13402324361. The reversal of 13402324343 is 34342320431.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13402324343 - 2¹⁴ = 13402307959 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13402324363) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31280 + ... + 166682.

It is an arithmetic number, because the mean of its divisors is an integer number (3350639682).

Almost surely, 2^13402324343 is an apocalyptic number.

13402324343 is a deficient number, since it is larger than the sum of its proper divisors (234385).

13402324343 is an equidigital number, since it uses as much as digits as its factorization.

13402324343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 234384.

The product of its (nonzero) digits is 20736, while the sum is 29.

Adding to 13402324343 its reverse (34342320431), we get a palindrome (47744644774).

The spelling of 13402324343 in words is "thirteen billion, four hundred two million, three hundred twenty-four thousand, three hundred forty-three".